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Terlampir.............,...........
Terlampir.............,...........
Jawab:
d. 2
Penjelasan dengan langkah-langkah:
[tex]\int\limits^2_1 {(3x^{2}-tx+t) } \, dx=6 \\x^3-\frac{t}{2}x^2+tx\left \{ {{2 \atop {1}} \right. =6\\{(2)^3-\frac{t}{2}(2)^2+t(2)}-[(1)^3-\frac{t}{2}(1)^3+t(1) =6\\ 8-2t+2t-1+\frac{t}{2}-t=6\\ 7-\frac{t}{2}=6\\ 1=\frac{t}{2}\\ t=2[/tex]
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